y^2-13y+36/3y-12

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Solution for y^2-13y+36/3y-12 equation: 


y in (-oo:+oo)

y^2-(13*y)+(36/3)*y-12 = 0

y^2-13*y+(36/3)*y-12 = 0

y^2-y-12 = 0

DELTA = (-1)^2-(-12*1*4)

DELTA = 49

DELTA > 0

y = (49^(1/2)+1)/(1*2) or y = (1-49^(1/2))/(1*2)

y = 4 or y = -3

y in { -3, 4 }

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